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Two simple harmonic motions are represented by the equations y1 = 0.1 sin(100πt + π/3)
y2 = 0.1 cos πt. The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is
- π/3
- -π/6
- π/6
- -π/3
Correct answer: -π/6
Solution
Velocity phase of 1 = pi/3 + pi/2; velocity phase of 2 (from y2=cos = sin(+pi/2)) = pi/2 + pi/2. Difference = (5pi/6) - (pi) = -pi/6.
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