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A spring having spring constant k is divided into two segments A and B such that their lengths are in the ratio l_A: l_B = 2: 3. The spring constant of segment A is
- 3k/5
- 2k/5
- k
- 5k/2
Correct answer: 5k/2
Solution
The spring constant of a segment is inversely proportional to its length. Since segment A is shorter than segment B, it will have a higher spring constant. Given the ratio of lengths, the spring constant for segment A can be calculated as 5k/2.
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