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ExamsJEE MainPhysics

The dimensions of B² / (2μ0), where B is magnetic field and μ0 is the magnetic permeability of vacuum, is:

  1. MLT−2
  2. ML2T−1
  3. ML2T−2
  4. ML−1T−2

Correct answer: ML−1T−2

Solution

B^2/(2*mu0) is magnetic energy density, which has the dimensions of pressure: energy/volume = (ML^2T^-2)/(L^3) = ML^-1T^-2.

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