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A student measures the time period of 100 oscillations of a simple pendulum four times. The data set is 90 s, 91 s, 95 s, and 92 s. If the minimum division in the measuring clock is 1 s, then the reported mean time should be:
- 92 ± 1.8 s
- 92 ± 3 s
- 92 ± 1.5 s
- 92 ± 5.0 s
Correct answer: 92 ± 1.5 s
Solution
Mean = (90+91+95+92)/4 = 92 s. Mean absolute deviation = (2+1+3+0)/4 = 1.5 s. Reported value = 92 +/- 1.5 s.
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