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In a single-slit diffraction pattern, what is the phase difference between the Huygens wavelet coming from one edge of the slit and the wavelet coming from the slit’s midpoint at the first dark fringe next to the central bright maximum?

1. π/2 radian
2. π radian
3. π/8 radian
4. π/4 radian

Correct answer: π radian

Solution

At the first dark fringe in a single-slit diffraction pattern, the path difference between the wavelets from the edges of the slit and the midpoint is equal to half the wavelength, which corresponds to a phase difference of π radians, leading to destructive interference.

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