Exams › JEE Main › Physics
Two small bar magnets P and Q are placed far apart with their centres lying on the X-axis. The magnetic axis of P is along the X-axis, while that of Q is along the Y-axis. At point R, which is exactly midway between the two centres, let B denote the magnitude of the magnetic induction produced by Q alone. The magnitude of the resultant magnetic induction at R due to both magnets is
- 3B
- √5B
- (√5/2) B
- B
Correct answer: √5B
Solution
The resultant magnetic induction at point R is found by vectorially adding the magnetic fields from both magnets. Since magnet P's field is along the X-axis and magnet Q's field is along the Y-axis, the resultant forms a right triangle, leading to the calculation of the resultant magnitude as √(B² + B²) = √5B.
Related JEE Main Physics questions
⚔️ Practice JEE Main Physics free + battle 1v1 →