Exams › JEE Main › Physics
A capacitor of capacitance C is initially charged and then allowed to discharge through a small coil of resistance R placed inside a thermally insulated block of mass m and specific heat capacity s. If the block’s temperature increases by ΔT, what was the potential difference V across the capacitor initially?
- mCΔT / s
- √(2mCΔT / s)
- √(2msΔT / C)
- msΔT / C
Correct answer: √(2msΔT / C)
Solution
The correct option is derived from the energy conservation principle, where the energy stored in the capacitor, given by (1/2)CV², is converted into heat energy absorbed by the block, which is calculated as msΔT. By equating these two forms of energy and solving for V, we find that V equals √(2msΔT / C).
Related JEE Main Physics questions
⚔️ Practice JEE Main Physics free + battle 1v1 →