StreakPeaked· Practice

ExamsJEE MainPhysics

A mixture containing 1 mole of helium and 1 mole of hydrogen is heated from 0°C to 100°C while the pressure is kept constant. How much heat must be supplied?

  1. 600 cal
  2. 1200 cal
  3. 1800 cal
  4. 3600 cal

Correct answer: 1200 cal

Solution

Q = (n_He*Cp_He + n_H2*Cp_H2)*dT = (5/2 R + 7/2 R)*100 = 6R*100 = 600R. With R = 2 cal/mol/K, Q = 1200 cal.

Related JEE Main Physics questions

⚔️ Practice JEE Main Physics free + battle 1v1 →