Exams › JEE Main › Maths
Find the number of values of theta with 0 < theta < pi for which the system (y + z)cos(3 theta) = (x*y*z)sin(3 theta); x*sin(3 theta) = 2*cos(3 theta)/y + 2*sin(3 theta)/z; (x*y*z)sin(3 theta) = (y + 2z)cos(3 theta) + y*sin(3 theta) has a solution (x0, y0, z0) with y0*z0 != 0.
- 1
- 2
- 3
- 4
Correct answer: 3
Solution
Reducing the system gives a determinant/consistency condition satisfied at three values of theta in (0, pi); the answer is 3.
Related JEE Main Maths questions
- If A is a square matrix, then the matrix product A A^T is a
- Let f(α)=[cosα, sinα; -sinα, cosα]. If α, β, and γ are the angles of a triangle, then the product f(α)f(β)f(γ) is equal to
- Let A, B, and C be n × n matrices. Which of the following statements is true?
- Given the matrix A_α = [cos α -sin α; sin α cos α], which of the following identities is true?
- Let A be a square matrix satisfying (A−2I)(A+I)=O. Then A−1 equals:
- A square matrix P obeys the relation P² = I - P, where I denotes the identity matrix. If Pⁿ = 5I - 8P, then the value of n is
⚔️ Practice JEE Main Maths free + battle 1v1 →