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Let f(α)=[cosα, sinα; -sinα, cosα]. If α, β, and γ are the angles of a triangle, then the product f(α)f(β)f(γ) is equal to
- I₂
- -I₂
- 0
- None of these
Correct answer: -I₂
Solution
Each matrix is a rotation by -a, so the product is a rotation by -(alpha+beta+gamma). In a triangle alpha+beta+gamma=pi, giving rotation by -pi, which is the matrix [[-1,0],[0,-1]] = -I_2.
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