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Show that sin(A - B)/(cos A cos B) + sin(B - C)/(cos B cos C) + sin(C - A)/(cos C cos A) = 0.
- True (identity holds; each term reduces to a difference of tangents that telescopes to 0)
- Equal to tan A + tan B + tan C
- Equal to 1
- Equal to tan A tan B tan C
Correct answer: True (identity holds; each term reduces to a difference of tangents that telescopes to 0)
Solution
Each fraction simplifies to a difference of tangents, and the three differences cancel, giving 0.
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