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If ABCD is a cyclic quadrilateral, find the value of sin(A) + sin(B) - sin(C) - sin(D).
- 0
- 1
- 2
- 4 sin(A) sin(B)
Correct answer: 0
Solution
Since C = 180 - A and D = 180 - B, sin(C) = sin(A) and sin(D) = sin(B), so the sum is sin A + sin B - sin A - sin B = 0.
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