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Let zₙ = cos(pi/((2n+1)(2n+3))) + i*sin(pi/((2n+1)(2n+3))). Evaluate the limit as n -> infinity of the product z₁ * z₂ * z₃ *... * zₙ.
- cos(pi/3) + i*sin(pi/3)
- cos(pi/6) + i*sin(pi/6)
- cos(5pi/6) + i*sin(5pi/6)
- cos(3pi/2) + i*sin(3pi/2)
Correct answer: cos(pi/6) + i*sin(pi/6)
Solution
The product equals cos(S) + i*sin(S) where S = sum of the arguments; the telescoping sum converges to pi/6.
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