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ExamsJEE MainMaths

For the quadratic equation 2(1+i)x² − 4(2−i)x − (5+3i) = 0, the root with the larger absolute value is

  1. (3−5i)/2
  2. (5−3i)/2
  3. (3−i)/2
  4. None of these

Correct answer: (3−5i)/2

Solution

Solving 2(1+i)x^2 -4(2-i)x -(5+3i)=0 gives roots x = (3-5i)/2 (modulus sqrt(34)/2 ~ 2.92) and x = (-1-i)/2 (modulus ~0.71). The root of larger absolute value is (3-5i)/2.

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