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ExamsJEE MainMaths

Evaluate (sin 75deg - sin 15deg) / (cos 75deg + cos 15deg).

  1. 0
  2. 1
  3. sqrt(3)
  4. 1/sqrt(3)

Correct answer: 1/sqrt(3)

Solution

Both expressions share the factor 2 cos45deg, leaving tan30deg = 1/sqrt(3).

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