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Simplify the expression sin((n+1)A)*sin((n-1)A) + cos((n+1)A)*cos((n-1)A).
- cos(2A)
- sin(2A)
- cos(2nA)
- 1
Correct answer: cos(2A)
Solution
The expression matches the cosine difference formula with X = (n+1)A and Y = (n-1)A, so it equals cos((n+1)A - (n-1)A) = cos(2A).
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