Correct answer: ~(R ∨ Q) → ~P
The statement (P ∧ (~R)) → ((~R) ∧ Q) is false only when P is true and R is false, which leads to the conclusion that if R is false, then P must also be false for the implication to hold. Thus, the statement ~(R ∨ Q) → ~P must also be false, as it asserts that if neither R nor Q is true, then P must be false, contradicting the earlier condition.