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The proposition ~(p → q) → [(~p) ∨ (~q)] is best classified as

1. a tautology
2. a contradiction
3. neither a tautology nor a contradiction
4. no definite conclusion can be drawn

Correct answer: a tautology

Solution

The proposition is a tautology because it is true for all possible truth values of p and q, meaning that the implication holds regardless of the truth values assigned to the variables.

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