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The expression ~(p → q) is logically equivalent to:

1. p ∧ q
2. ~p ∧ ~q
3. p ∧ ~q
4. ~p ∧ q

Correct answer: p ∧ ~q

Solution

p->q is equivalent to ~p OR q. Negating gives ~(~p OR q) = p AND ~q. So the answer is p AND ~q.

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