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The tangents to the curve y = (x - 2)² - 1 at its points of intersection with the line x - y = 3, intersect at the point:
- (5/2, -1)
- (-5/2, -1)
- (5/2, 1)
- (-5/2, 1)
Correct answer: (5/2, -1)
Solution
The correct option is right because the tangents to the curve at the intersection points with the line x - y = 3 can be calculated, and their intersection point is found to be (5/2, -1), which satisfies both the curve and the line equations.
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