Exams › JEE Main › Maths
Given a=(1)/(√(10))(3î+k̂) and b=(1)/(7)(2î+3ĵ-6k̂), find the value of (2a-b) [(a×b)×(a+2b) ].
- -3
- 5
- 3
- -5
Correct answer: -5
Solution
The expression involves vector operations where the cross product and dot product are calculated. The correct option is -5 because the resulting vector from the cross product is orthogonal to both vectors involved, and the dot product with the linear combination of vectors yields this specific value.
Related JEE Main Maths questions
- If ((â × b̂) × (ĉ × d̂)) · (â × d̂) = 0, which statement must always hold?
- For four points A, B, C and D in space, if the dot product of vectors AB and CD is given by k times [|AD|² + |BC|² - |AC|² - |BD|²], then what is the value of k?
- Three vectors →a, →b and →c have magnitudes |→a| = 4, |→b| = 4 and |→c| = 2. If →a is orthogonal to (→b + →c), →b is orthogonal to (→c + →a), and →c is orthogonal to (→a + →b), then the magnitude of (→a + →b + →c) is:
- The position vectors of the vertices A, B and C of triangle ABC are 4î + 7ĵ + 8k̂, 2î + 3ĵ + 4k̂ and 2î + 5ĵ + 7k̂ respectively. The position vector of the point where the internal bisector of angle A intersects BC is
- Let a=a₁î+a₂ĵ+a₃k̂, b=b₁î+b₂ĵ+b₃k̂, and c=c₁î+c₂ĵ+c₃k̂ be three non-zero vectors. Suppose c is a unit vector perpendicular to both a and b. If the angle between a and b is π/6, then the value of |[a₁, a₂, a₃; b₁, b₂, b₃; c₁, c₂, c₃] | is
- Let a, b, and c be three vectors that are not in the same plane. Define p = (b × c)/([abc]), q = (c × a)/([abc]), and r = (a × b)/([abc]). Then the value of (a+b)·p + (b+c)·q + (c+a)·r is
⚔️ Practice JEE Main Maths free + battle 1v1 →