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Let a=a₁î+a₂ĵ+a₃k̂, b=b₁î+b₂ĵ+b₃k̂, and c=c₁î+c₂ĵ+c₃k̂ be three non-zero vectors. Suppose c is a unit vector perpendicular to both a and b. If the angle between a and b is π/6, then the value of |[a₁, a₂, a₃; b₁, b₂, b₃; c₁, c₂, c₃] | is
- 0
- 1
- (1)/(4)|a|²|b|²
- (3)/(4)|a|²|b|²
Correct answer: (1)/(4)|a|²|b|²
Solution
c is a unit vector along a x b, so [a b c] = c.(a x b) = |a x b| = |a||b| sin(pi/6) = |a||b|/2. The squared value (as the options are framed) is (1/4)|a|^2|b|^2.
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