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A triangular park is enclosed on two sides by a fence and on the third side by a straight river bank. The two sides having fence are of same length x. The maximum area enclosed by the park is
- 3/2 x²
- √(x³/8)
- 1/2 x²
- πx²
Correct answer: 1/2 x²
Solution
With two fenced sides of length x enclosing angle theta, area = (1/2)x^2 sin(theta), which is maximal when theta = 90 degrees, giving maximum area = x^2/2.
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