Correct answer: 1
The roots α and β of the equation x² - x + 1 = 0 can be expressed in terms of complex numbers, specifically as α = e^(iπ/3) and β = e^(-iπ/3). Using De Moivre's theorem, we find that αⁿ + βⁿ can be computed using the periodicity of complex exponentials, leading to α²⁰⁰⁹ + β²⁰⁰⁹ = 1.