Exams › JEE Main › Maths
Given that the cube roots of unity are 1, ω, and ω², which of the following is the set of roots of the equation (x - 1)³ + 8 = 0?
- -1, -1 + 2ω, -1 - 2ω²
- -1, -1, -1
- -1, 1 - 2ω, 1 - 2ω²
- -1, 1 + 2ω, 1 + 2ω²
Correct answer: -1, 1 - 2ω, 1 - 2ω²
Solution
The equation can be rewritten as (x - 1)³ = -8, which simplifies to (x - 1) = -2, leading to x = -1. The other roots are derived from the cube roots of -8, which correspond to the expressions 1 - 2ω and 1 - 2ω², making option C the correct choice.
Related JEE Main Maths questions
⚔️ Practice JEE Main Maths free + battle 1v1 →