Exams › JEE Main › Maths
Let A be the 2×2 matrix [[1, 1], [1, 1]]. What is A raised to the 100th power?
- [[1, 1], [1, 1]]
- 2⁹⁹ [[1, 1], [1, 1]]
- 2¹⁰⁰ [[1, 1], [1, 1]]
- [[2, 2], [2, 2]]
Correct answer: 2⁹⁹ [[1, 1], [1, 1]]
Solution
Since A=[[1,1],[1,1]] gives A^2=[[2,2],[2,2]]=2A, by induction A^n = 2^(n-1) A. Hence A^100 = 2^99 [[1,1],[1,1]].
Related JEE Main Maths questions
- If A is a square matrix, then the matrix product A A^T is a
- Let f(α)=[cosα, sinα; -sinα, cosα]. If α, β, and γ are the angles of a triangle, then the product f(α)f(β)f(γ) is equal to
- Let A, B, and C be n × n matrices. Which of the following statements is true?
- Given the matrix A_α = [cos α -sin α; sin α cos α], which of the following identities is true?
- Let A be a square matrix satisfying (A−2I)(A+I)=O. Then A−1 equals:
- A square matrix P obeys the relation P² = I - P, where I denotes the identity matrix. If Pⁿ = 5I - 8P, then the value of n is
⚔️ Practice JEE Main Maths free + battle 1v1 →