In a right-angled triangle ABC with ∠C = 90°, the value of (a² - b²)/(a² + b²) is:
sin(A + B)
sin(A - B)
cos(A + B)
sin((A - B)/2)
Correct answer: sin(A - B)
Solution
The expression (a² - b²)/(a² + b²) simplifies to sin(A - B) due to the relationships between the sides of the triangle and the angles, where a and b are the lengths of the sides opposite angles A and B respectively.