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ExamsJEE MainMaths

In a right-angled triangle ABC with ∠C = 90°, the value of (a² - b²)/(a² + b²) is:

  1. sin(A + B)
  2. sin(A - B)
  3. cos(A + B)
  4. sin((A - B)/2)

Correct answer: sin(A - B)

Solution

The expression (a² - b²)/(a² + b²) simplifies to sin(A - B) due to the relationships between the sides of the triangle and the angles, where a and b are the lengths of the sides opposite angles A and B respectively.

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