Exams › JEE Main › Maths
Given that matrix A = [6 8 5; 4 2 3; 9 7 1] can be expressed as the sum of a symmetric matrix B and a skew-symmetric matrix C, determine B.
- [6 6 7; 6 2 5; 7 5 1]
- [0 2 −2; −2 5 −2; 2 2 0]
- [6 6 7; −6 2 −5; −7 5 1]
- [0 6 −2; 2 0 −2; −2 −2 0]
Correct answer: [6 6 7; 6 2 5; 7 5 1]
Solution
A + A^T = [[12,12,14],[12,4,10],[14,10,2]], so B = (A+A^T)/2 = [[6,6,7],[6,2,5],[7,5,1]]. (Option 1 shown is the skew-symmetric part, not B.)
Related JEE Main Maths questions
- If A is a square matrix, then the matrix product A A^T is a
- Let f(α)=[cosα, sinα; -sinα, cosα]. If α, β, and γ are the angles of a triangle, then the product f(α)f(β)f(γ) is equal to
- Let A, B, and C be n × n matrices. Which of the following statements is true?
- Given the matrix A_α = [cos α -sin α; sin α cos α], which of the following identities is true?
- Let A be a square matrix satisfying (A−2I)(A+I)=O. Then A−1 equals:
- A square matrix P obeys the relation P² = I - P, where I denotes the identity matrix. If Pⁿ = 5I - 8P, then the value of n is
⚔️ Practice JEE Main Maths free + battle 1v1 →