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ExamsJEE MainMaths

Evaluate the value of tancos⁻¹(1/√(82)) - sin⁻¹(5/√(26)).

  1. 2/23
  2. 4/31
  3. 29/3
  4. 6/13

Correct answer: 2/23

Solution

The expression involves the tangent of the difference of two inverse trigonometric functions. By using the identities for cosine and sine, we can simplify the expression to find that the value of tan(cos⁻¹(1/sqrt{82}) - sin⁻¹(5/sqrt{26})) equals 2/23.

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