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Determine the range of the function f(x) = sin⁻¹x + tan⁻¹x + sec⁻¹x.
- (π/4, 3π/4)
- [π/4, 3π/4]
- {π/4, 3π/4}
- None of these
Correct answer: {π/4, 3π/4}
Solution
sin^-1 needs |x|<=1 and sec^-1 needs |x|>=1, so the domain is just x=+-1. At x=1: pi/2+pi/4+0 = 3pi/4. At x=-1: -pi/2-pi/4+pi = pi/4. Range = {pi/4, 3pi/4}.
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