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The statement (p ∧ q) ⇒ p is

1. always true, i.e., a tautology
2. always false, i.e., a contradiction
3. neither a tautology nor a contradiction
4. none of the above

Correct answer: always true, i.e., a tautology

Solution

The statement (p nd q) implies p is always true because if both p and q are true, then p must be true as well, making the implication valid in all scenarios.

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