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For the compound proposition (~p → ~q) ∧ (~q → ~p), what is the sequence of truth values in the final column of its truth table?

1. TTTF
2. FTTF
3. TFFT
4. TTTT

Correct answer: TFFT

Solution

(~p->~q)/\(~q->~p) = (~p<->~q) = (p<->q). For (p,q) = TT, TF, FT, FF the biconditional gives T, F, F, T, so the final column is TFFT.

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