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ExamsJEE MainMaths

Let α and β be the zeros of the quadratic equation 2x² + 6x + b = 0, where b < 0. Then the value of α/β + β/α is less than:

  1. 1
  2. −1
  3. 2
  4. −2

Correct answer: −2

Solution

Sum=-3, product=b/2. alpha/beta+beta/alpha=((alpha+beta)^2-2*product)/product=(9-b)/(b/2)=18/b-2. Since b<0, 18/b<0, so the value is < -2.

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