Exams › JEE Main › Chemistry
In which of the following pairs does the first species have greater resonance (delocalization) energy than the second?
- a conjugated triene and benzene
- a conjugated diene anion and cyclopentadienyl cation
- a conjugated enamine and a conjugated aminoalkene
- None of these
Correct answer: None of these
Solution
Benzene is aromatic (6 pi electrons, 4n+2) and has much larger resonance energy than an open-chain conjugated triene, so the first < second in pair 1. The cyclopentadienyl cation is anti-aromatic/non-aromatic but the comparison still does not make the open diene anion larger in a clean way; and 'enamine' vs 'aminoalkene' describe essentially the same delocalized N-C=C system, so neither is clearly greater. In none of the pairs is the first species reliably higher in resonance energy, so the answer is 'None of these'.
Related JEE Main Chemistry questions
- Although the electronegativity gap between N and F is larger than that between N and H, ammonia has a dipole moment of 1.5 D while nitrogen trifluoride has only 0.2 D. The reason is that
- When N₂ is converted into N₂⁺, the dissociation energy of the N–N bond ______, and when O₂ is converted into O₂⁺, the dissociation energy of the O–O bond ______.
- From the ions listed below, which pair has geometries that can be accounted for by the same type of orbital hybridization? NO₂⁻, NO₃⁻, NH₂⁻, NH₄⁺, SCN⁻
- Atoms A and B have electronegativities of 1.20 and 4.0, respectively. What is the percentage ionic character of the A–B bond?
- In the phosphate ion, PO₄³⁻, what is the formal charge on an oxygen atom that is singly bonded to phosphorus in a P–O bond?
- Among the following species, which one has no unpaired electrons?
⚔️ Practice JEE Main Chemistry free + battle 1v1 →