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In the reaction sequence: NaCl + K2Cr2O7 + conc. H2SO4 -> (A) + side products (A) + NaOH -> (B) + side product (B) + dilute H2SO4 + H2O2 -> (C) + side product what is the sum of the total number of atoms present in one molecule each of (A), (B) and (C)?

1. 18
2. 20
3. 22
4. 16

Correct answer: 18

Solution

(A) chromyl chloride CrO2Cl2 has 5 atoms, (B) sodium chromate Na2CrO4 has 7 atoms, and (C) chromium pentoxide CrO5 has 6 atoms, summing to 18.

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