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A transition metal M gives a volatile chloride whose vapour density is 94.8. If this chloride contains 74.75% chlorine by mass, what is the formula of the metal chloride?

1. MCl₃
2. MCl₂
3. MCl₄
4. MCl₅

Correct answer: MCl₄

Solution

MW = 2 x 94.8 = 189.6; Cl mass = 0.7475 x 189.6 = 141.7 g -> 141.7/35.5 = 4 Cl atoms, so MCl4. Stored MCl2 is wrong.

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