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When CuSO4 reacts with KI in dilute H2SO4, a blue-coloured species X is present and a diatomic covalent molecule Y is liberated. Identify X and Y.

1. X = I2, Y = [Cu(H2O)4]2+
2. X = [Cu(H2O)4]2+, Y = I2
3. X = [Cu(H2O)4]4+, Y = I2
4. X = [Cu(H2O)5]2+, Y = I2

Correct answer: X = [Cu(H2O)4]2+, Y = I2

Solution

Cu2+ oxidises I- to the diatomic molecule I2 (Y) while being reduced to insoluble CuI; the blue species X is the hydrated copper(II) ion [Cu(H2O)4]2+.

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