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When I⁻ is oxidised by MnO4⁻ in alkaline medium, the iodine-containing product is:

1. IO3⁻
2. I2
3. IO⁻
4. IO4⁻

Correct answer: IO3⁻

Solution

In alkaline medium MnO4⁻ oxidises I⁻ to iodate IO3⁻ (while Mn goes to MnO2).

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