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Arrange the following sulphur-containing anions in order of increasing oxidation state of sulphur: SO3²⁻, S2O4²⁻ and S2O6²⁻.

1. S2O6²⁻ < S2O4²⁻ < SO3²⁻
2. SO6²⁻ < S2O4²⁻ < S2O6²⁻
3. S2O4²⁻ < SO3²⁻ < S2O6²⁻
4. S2O4²⁻ < S2O6²⁻ < SO3²⁻

Correct answer: S2O4²⁻ < SO3²⁻ < S2O6²⁻

Solution

S oxidation states: S2O4^2- = +3, SO3^2- = +4, S2O6^2- = +5, so increasing order is S2O4^2- < SO3^2- < S2O6^2- (option 2). The stored order is wrong.

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