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For the permanganate ion in different media: MnO4- + x e- -> MnO4²- (alkaline), MnO4- + y e- -> Mn2+ (acidic), and MnO4- + z e- -> MnO2 (neutral). What are x, y and z respectively?

1. 1, 2, 3
2. 1, 5, 3
3. 1, 3, 5
4. 5, 3, 1

Correct answer: 1, 5, 3

Solution

Mn goes +7->+6 (1 e-) in alkaline medium, +7->+2 (5 e-) in acidic, and +7->+4 (3 e-) in neutral medium.

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