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According to molecular orbital theory, what is the ratio of the number of pi electrons in C2 to that in B2?
- 1:1
- 2:1
- 1:2
- 3:2
Correct answer: 2:1
Solution
In B2 (6 valence-region electrons in this scheme) 2 electrons occupy pi(2p) orbitals, while in C2 all 4 bonding electrons occupy the pi(2p) orbitals, giving a pi-electron ratio of 4:2 = 2:1.
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