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Let x, y and z be the oxidation states of the transition-metal atom in K2Cr2O7, KMnO4 and K2FeO4 respectively. What is the value of x + y + z?

1. 19
2. 18
3. 20
4. 21

Correct answer: 19

Solution

Cr in K2Cr2O7 is +6, Mn in KMnO4 is +7 and Fe in K2FeO4 is +6, so the sum is 6 + 7 + 6 = 19.

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