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Arrange the following anions in the correct sequence of decreasing polarizability: I-, Br-, Cl-, F-.
- I- > Br- > Cl- > F-
- I- > Br- > F- > Cl-
- I- < Br- < Cl- < F-
- I- < Br- < F- < Cl-
Correct answer: I- > Br- > Cl- > F-
Solution
Larger ions hold their outer electron cloud more loosely, so they are more easily distorted (more polarizable). Since I- is the largest halide and F- the smallest, polarizability follows I- > Br- > Cl- > F-.
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