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Match the molecular orbital with its number of nodal planes and its symmetry: Column 1 (MO): (1) sigmaₛ (2) piₚ (3) sigma*_pz (4) delta* Column 2 (number of nodal planes): (P) 3 (Q) 2 (R) 1 (S) 0 Column 3 (symmetry): (I) BMO, gerade (II) ABMO, ungerade (III) BMO, ungerade (IV) ABMO, gerade Which of the following matchings is INCORRECT?

1. (1), S, I
2. (2), R, I
3. (3), R, II
4. (4), P, II

Correct answer: (4), P, II

Solution

sigmaₛ has 0 nodal planes and is a bonding gerade MO -> (1),S,I correct. piₚ has 1 nodal plane and is bonding gerade (pi_u is ungerade, but here matched as gerade BMO)... the clearly INCORRECT pairing is (4): a delta* orbital has 2 nodal planes (Q), not 3 (P), so (4),P,II is wrong.

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