Exams › JEE Main › Chemistry
Pick the CORRECT trend among these statements: (A) NaF < MgF2 < AlF3: covalent character (B) NaF < MgF2 < AlF3: melting point (C) NaF < MgF2 < AlF3: lattice energy (D) NaF > MgF2 > AlF3: polarising power of the cation
- (A) NaF < MgF2 < AlF3: covalent character order.
- (B) NaF < MgF2 < AlF3: melting point order
- (C) NaF < MgF2 < AlF3: lattice energy order
- (D) NaF > MgF2 > AlF3: order of polarising power of cation.
Correct answer: (A) NaF < MgF2 < AlF3: covalent character order.
Solution
Polarising power increases Na+ < Mg2+ < Al3+, so covalent character increases NaF < MgF2 < AlF3 (A is correct). Because AlF3 is more covalent it does NOT have the highest melting/lattice point in the simple ionic sense; (D) reverses the true polarising-power order, and (B)/(C) are not the intended correct trend.
Related JEE Main Chemistry questions
- Although the electronegativity gap between N and F is larger than that between N and H, ammonia has a dipole moment of 1.5 D while nitrogen trifluoride has only 0.2 D. The reason is that
- When N₂ is converted into N₂⁺, the dissociation energy of the N–N bond ______, and when O₂ is converted into O₂⁺, the dissociation energy of the O–O bond ______.
- From the ions listed below, which pair has geometries that can be accounted for by the same type of orbital hybridization? NO₂⁻, NO₃⁻, NH₂⁻, NH₄⁺, SCN⁻
- Atoms A and B have electronegativities of 1.20 and 4.0, respectively. What is the percentage ionic character of the A–B bond?
- In the phosphate ion, PO₄³⁻, what is the formal charge on an oxygen atom that is singly bonded to phosphorus in a P–O bond?
- Among the following species, which one has no unpaired electrons?
⚔️ Practice JEE Main Chemistry free + battle 1v1 →