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Match each diatomic species in Column I with its property/properties in Column II. Column I: (A) B2 (B) N2 (C) O2⁻ (D) O2⁺ Column II: (P) Paramagnetic (Q) Undergoes oxidation (R) Undergoes reduction (S) Bond order > 2 (T) Mixing of s and p orbitals occurs

1. (A)-P,T; (B)-S,T; (C)-P,R; (D)-P,Q,S
2. (A)-S; (B)-P; (C)-S; (D)-R only
3. (A)-P; (B)-S; (C)-Q; (D)-R
4. (A)-P,S; (B)-T; (C)-R; (D)-Q

Correct answer: (A)-P,T; (B)-S,T; (C)-P,R; (D)-P,Q,S

Solution

B2 has two unpaired electrons (paramagnetic) and shows s-p mixing; N2 has bond order 3 (>2) with s-p mixing; superoxide O2⁻ is paramagnetic and tends to be reduced; O2⁺ is paramagnetic, bond order 2.5 (>2), and is formed by/undergoes oxidation.

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