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[Cr(H2O)6]Cl3 (at. no. of Cr = 24) has a magnetic moment of 3.83 B.M. The correct distribution of 3d electrons in the chromium of the complex is
- 3d⁴ 1, 3d² x²-y², 3d² yz
- 3d⁴ 1, 3d² yz, 3d² xz
- 3d⁴ 1, 3d² x²-y², 3d² z²
- 3d⁴ 2, 3d² x²-y², 3d² xz
Correct answer: 3d⁴ 1, 3d² x²-y², 3d² z²
Solution
The magnetic moment of 3.83 B.M. corresponds to 3 unpaired electrons, which is consistent with the 3d⁴ 1, 3d² x²-y², 3d² z² configuration.
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