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What is the spin-only magnetic moment, expressed in Bohr magnetons (μB), for Ni2+ in aqueous solution? (Atomic number of Ni = 28)
- 6
- 1.73
- 2.82
- 4.90
Correct answer: 2.82
Solution
Ni2+ = [Ar]3d8 has 2 unpaired electrons, so spin-only moment = sqrt(n(n+2)) = sqrt(2*4) = sqrt(8) = 2.83 BM (~2.82).
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