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For the following coordination species, identify the correct sequence of spin-only paramagnetic moments: I. [FeF6]3− II. [CrF6]3− III. [V(H2O)6]3+ IV. [Ti(H2O)6]3+

1. I > II > III > IV
2. I < II < III < IV
3. I > III > IV > II
4. I > II > IV > III

Correct answer: I > II > III > IV

Solution

[FeF6]3- is d5 high-spin (5 unpaired), [CrF6]3- is d3 (3), [V(H2O)6]3+ is d2 (2), [Ti(H2O)6]3+ is d1 (1). Spin-only moment rises with unpaired electrons, so I > II > III > IV.

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