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The IUPAC name of the following compound is CH3–C(H)=C(H)–C≡C–CH2CH3

1. (E)-2-hepten-4-yne
2. (Z)-5-hepten-3-yne
3. (E)-5-hepten-3-yne
4. (Z)-2-hepten-4-yne

Correct answer: (E)-2-hepten-4-yne

Solution

The correct option is (E)-2-hepten-4-yne because it accurately reflects the structure of the compound, which has a double bond at the second carbon and a triple bond at the fourth carbon, with the substituents arranged in the E configuration.

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